14 KiB
Linked List (Doubly)
The core module provides a useful data structure known as a doubly linked list. Briefly, a doubly linked list is a series of records (a.k.a. nodes) which has information on the previous node, the next node, and its own value (or data).
Getting Started
To create a doubly linked list, all you have to do is to import and create a new instance of it:
import { LinkedList } from '@abp/ng.core';
const list = new LinkedList();
The constructor does not get any parameters.
Usage
How to Add New Nodes
There are a few methods to create new nodes in a linked list and all of them are separately available as well as revealed from an add method.
addHead(value: T): ListNode<T>
Adds a node with given value as the first node in list:
list.addHead('a');
// "a"
list.addHead('b');
// "b" <-> "a"
list.addHead('c');
// "c" <-> "b" <-> "a"
addTail(value: T): ListNode<T>
Adds a node with given value as the last node in list:
list.addTail('a');
// "a"
list.addTail('b');
// "a" <-> "b"
list.addTail('c');
// "a" <-> "b" <-> "c"
addAfter(value: T, previousValue: T, compareFn = compare): ListNode<T>
Adds a node with given value after the first node that has the previous value:
list.addTail('a');
list.addTail('b');
list.addTail('b');
list.addTail('c');
// "a" <-> "b" <-> "b" <-> "c"
list.addAfter('x', 'b');
// "a" <-> "b" <-> "x" <-> "b" <-> "c"
You may pass a custom compare function to detect the searched value:
list.addTail({ x: 1 });
list.addTail({ x: 2 });
list.addTail({ x: 3 });
// {"x":1} <-> {"x":2} <-> {"x":3}
list.addAfter({ x: 0 }, { x: 2 }, (v1, v2) => v1.x === v2.x);
// {"x":1} <-> {"x":2} <-> {"x":0} <-> {"x":3}
The default compare function checks deep equality, so you will rarely need to pass that parameter.
addBefore(value: T, nextValue: T, compareFn = compare): ListNode<T>
Adds a node with given value before the first node that has the next value:
list.addTail('a');
list.addTail('b');
list.addTail('b');
list.addTail('c');
// "a" <-> "b" <-> "b" <-> "c"
list.addBefore('x', 'b');
// "a" <-> "x" <-> "b" <-> "b" <-> "c"
You may pass a custom compare function to detect the searched value:
list.addTail({ x: 1 });
list.addTail({ x: 2 });
list.addTail({ x: 3 });
// {"x":1} <-> {"x":2} <-> {"x":3}
list.addBefore({ x: 0 }, { x: 2 }, (v1, v2) => v1.x === v2.x);
// {"x":1} <-> {"x":0} <-> {"x":2} <-> {"x":3}
The default compare function checks deep equality, so you will rarely need to pass that parameter.
addByIndex(value: T, position: number): ListNode<T>
Adds a node with given value at the specified position in the list:
list.addTail('a');
list.addTail('b');
list.addTail('c');
// "a" <-> "b" <-> "c"
list.addByIndex('x', 2);
// "a" <-> "b" <-> "x" <-> "c"
add(value: T).head(): ListNode<T>
Adds a node with given value as the first node in list:
list.add('a').head();
// "a"
list.add('b').head();
// "b" <-> "a"
list.add('c').head();
// "c" <-> "b" <-> "a"
This is an alternative API for
addHead.
add(value: T).tail(): ListNode<T>
Adds a node with given value as the last node in list:
list.add('a').tail();
// "a"
list.add('b').tail();
// "a" <-> "b"
list.add('c').tail();
// "a" <-> "b" <-> "c"
This is an alternative API for
addTail.
add(value: T).after(previousValue: T, compareFn = compare): ListNode<T>
Adds a node with given value after the first node that has the previous value:
list.add('a').tail();
list.add('b').tail();
list.add('b').tail();
list.add('c').tail();
// "a" <-> "b" <-> "b" <-> "c"
list.add('x').after('b');
// "a" <-> "b" <-> "x" <-> "b" <-> "c"
You may pass a custom compare function to detect the searched value:
list.add({ x: 1 }).tail();
list.add({ x: 2 }).tail();
list.add({ x: 3 }).tail();
// {"x":1} <-> {"x":2} <-> {"x":3}
list.add({ x: 0 }).after({ x: 2 }, (v1, v2) => v1.x === v2.x);
// {"x":1} <-> {"x":2} <-> {"x":0} <-> {"x":3}
This is an alternative API for
addAfter.The default compare function checks deep equality, so you will rarely need to pass that parameter.
add(value: T).before(nextValue: T, compareFn = compare): ListNode<T>
Adds a node with given value before the first node that has the next value:
list.add('a').tail();
list.add('b').tail();
list.add('b').tail();
list.add('c').tail();
// "a" <-> "b" <-> "b" <-> "c"
list.add('x').before('b');
// "a" <-> "x" <-> "b" <-> "b" <-> "c"
You may pass a custom compare function to detect the searched value:
list.add({ x: 1 }).tail();
list.add({ x: 2 }).tail();
list.add({ x: 3 }).tail();
// {"x":1} <-> {"x":2} <-> {"x":3}
list.add({ x: 0 }).before({ x: 2 }, (v1, v2) => v1.x === v2.x);
// {"x":1} <-> {"x":0} <-> {"x":2} <-> {"x":3}
This is an alternative API for
addBefore.The default compare function checks deep equality, so you will rarely need to pass that parameter.
add(value: T).byIndex(position: number): ListNode<T>
Adds a node with given value at the specified position in the list:
list.add('a').tail();
list.add('b').tail();
list.add('c').tail();
// "a" <-> "b" <-> "c"
list.add('x').byIndex(2);
// "a" <-> "b" <-> "x" <-> "c"
This is an alternative API for
addByIndex.
How to Remove Nodes
There are a few methods to remove nodes from a linked list and all of them are separately available as well as revealed from a drop method.
dropHead(): ListNode<T> | undefined
Removes the first node from the list:
list.addTail('a');
list.addTail('b');
list.addTail('c');
// "a" <-> "b" <-> "c"
list.dropHead();
// "b" <-> "c"
dropTail(): ListNode<T> | undefined
Removes the last node from the list:
list.addTail('a');
list.addTail('b');
list.addTail('c');
// "a" <-> "b" <-> "c"
list.dropTail();
// "a" <-> "b"
dropByIndex(position: number): ListNode<T> | undefined
Removes the node with the specified position from the list:
list.addTail('a');
list.addTail('b');
list.addTail('c');
// "a" <-> "b" <-> "c"
list.dropByIndex(1);
// "a" <-> "c"
dropByValue(value: T, compareFn = compare): ListNode<T> | undefined
Removes the first node with given value from the list:
list.addTail('a');
list.addTail('x');
list.addTail('b');
list.addTail('x');
list.addTail('c');
// "a" <-> "x" <-> "b" <-> "x" <-> "c"
list.dropByValue('x');
// "a" <-> "b" <-> "x" <-> "c"
You may pass a custom compare function to detect the searched value:
list.addTail({ x: 1 });
list.addTail({ x: 0 });
list.addTail({ x: 2 });
list.addTail({ x: 0 });
list.addTail({ x: 3 });
// {"x":1} <-> {"x":0} <-> {"x":2} <-> {"x":0} <-> {"x":3}
list.dropByValue({ x: 0 }, (v1, v2) => v1.x === v2.x);
// {"x":1} <-> {"x":2} <-> {"x":0} <-> {"x":3}
The default compare function checks deep equality, so you will rarely need to pass that parameter.
dropByValueAll(value: T, compareFn = compare): ListNode<T>[]
Removes all nodes with given value from the list:
list.addTail('a');
list.addTail('x');
list.addTail('b');
list.addTail('x');
list.addTail('c');
// "a" <-> "x" <-> "b" <-> "x" <-> "c"
list.dropByValueAll('x');
// "a" <-> "b" <-> "c"
You may pass a custom compare function to detect the searched value:
list.addTail({ x: 1 });
list.addTail({ x: 0 });
list.addTail({ x: 2 });
list.addTail({ x: 0 });
list.addTail({ x: 3 });
// {"x":1} <-> {"x":0} <-> {"x":2} <-> {"x":0} <-> {"x":3}
list.dropByValue({ x: 0 }, (v1, v2) => v1.x === v2.x);
// {"x":1} <-> {"x":2} <-> {"x":3}
The default compare function checks deep equality, so you will rarely need to pass that parameter.
drop().head(): ListNode<T> | undefined
Removes the first node in list:
list.add('a').tail();
list.add('b').tail();
list.add('c').tail();
// "a" <-> "b" <-> "c"
list.drop().head();
// "b" <-> "c"
This is an alternative API for
dropHead.
drop().tail(): ListNode<T> | undefined
Removes the last node in list:
list.add('a').tail();
list.add('b').tail();
list.add('c').tail();
// "a" <-> "b" <-> "c"
list.drop().tail();
// "a" <-> "b"
This is an alternative API for
dropTail.
drop().byIndex(position: number): ListNode<T> | undefined
Removes the node with the specified position from the list:
list.add('a').tail();
list.add('b').tail();
list.add('c').tail();
// "a" <-> "b" <-> "c"
list.drop().byIndex(1);
// "a" <-> "c"
This is an alternative API for
dropByIndex.
drop().byValue(value: T, compareFn = compare): ListNode<T> | undefined
Removes the first node with given value from the list:
list.add('a').tail();
list.add('x').tail();
list.add('b').tail();
list.add('x').tail();
list.add('c').tail();
// "a" <-> "x" <-> "b" <-> "x" <-> "c"
list.drop().byValue('x');
// "a" <-> "b" <-> "x" <-> "c"
You may pass a custom compare function to detect the searched value:
list.add({ x: 1 }).tail();
list.add({ x: 0 }).tail();
list.add({ x: 2 }).tail();
list.add({ x: 0 }).tail();
list.add({ x: 3 }).tail();
// {"x":1} <-> {"x":0} <-> {"x":2} <-> {"x":0} <-> {"x":3}
list.drop().byValue({ x: 0 }, (v1, v2) => v1.x === v2.x);
// {"x":1} <-> {"x":2} <-> {"x":0} <-> {"x":3}
This is an alternative API for
dropByValue.The default compare function checks deep equality, so you will rarely need to pass that parameter.
drop().byValueAll(value: T, compareFn = compare): ListNode<T>[]
Removes all nodes with given value from the list:
list.add('a').tail();
list.add('x').tail();
list.add('b').tail();
list.add('x').tail();
list.add('c').tail();
// "a" <-> "x" <-> "b" <-> "x" <-> "c"
list.drop().byValueAll('x');
// "a" <-> "b" <-> "c"
You may pass a custom compare function to detect the searched value:
list.add({ x: 1 }).tail();
list.add({ x: 0 }).tail();
list.add({ x: 2 }).tail();
list.add({ x: 0 }).tail();
list.add({ x: 3 }).tail();
// {"x":1} <-> {"x":0} <-> {"x":2} <-> {"x":0} <-> {"x":3}
list.drop().byValueAll({ x: 0 }, (v1, v2) => v1.x === v2.x);
// {"x":1} <-> {"x":2} <-> {"x":3}
This is an alternative API for
dropByValueAll.The default compare function checks deep equality, so you will rarely need to pass that parameter.
How to Find Nodes
There are a few methods to find specific nodes in a linked list.
find(predicate: ListIteratorFunction<T>): ListNode<T> | undefined
Finds the first node from the list that matches the given predicate:
list.addTail('a');
list.addTail('b');
list.addTail('b');
list.addTail('c');
// "a" <-> "b" <-> "b" <-> "c"
const found = list.find(node => node.value === 'b');
/*
found.value === "b"
found.previous.value === "a"
found.next.value === "b"
*/
findIndex(predicate: ListIteratorFunction<T>): number
Finds the position of the first node from the list that matches the given predicate:
list.addTail('a');
list.addTail('b');
list.addTail('b');
list.addTail('c');
// "a" <-> "b" <-> "b" <-> "c"
const i0 = list.findIndex(node => node.next && node.next.value === 'b');
const i1 = list.findIndex(node => node.value === 'b');
const i2 = list.findIndex(node => node.previous && node.previous.value === 'b');
const i3 = list.findIndex(node => node.value === 'x');
/*
i0 === 0
i1 === 1
i2 === 2
i3 === -1
*/
get(position: number): ListNode<T> | undefined
Finds and returns the node with specific position in the list:
list.addTail('a');
list.addTail('b');
list.addTail('c');
// "a" <-> "b" <-> "c"
const found = list.get(1);
/*
found.value === "b"
found.previous.value === "a"
found.next.value === "c"
*/
indexOf(value: T, compareFn = compare): number
Finds the position of the first node from the list that has the given value:
list.addTail('a');
list.addTail('b');
list.addTail('b');
list.addTail('c');
// "a" <-> "b" <-> "b" <-> "c"
const i0 = list.indexOf('a');
const i1 = list.indexOf('b');
const i2 = list.indexOf('c');
const i3 = list.indexOf('x');
/*
i0 === 0
i1 === 1
i2 === 3
i3 === -1
*/
You may pass a custom compare function to detect the searched value:
list.addTail({ x: 1 });
list.addTail({ x: 0 });
list.addTail({ x: 2 });
list.addTail({ x: 0 });
list.addTail({ x: 3 });
// {"x":1} <-> {"x":0} <-> {"x":2} <-> {"x":0} <-> {"x":3}
const i0 = indexOf({ x: 1 }, (v1, v2) => v1.x === v2.x);
const i1 = indexOf({ x: 2 }, (v1, v2) => v1.x === v2.x);
const i2 = indexOf({ x: 3 }, (v1, v2) => v1.x === v2.x);
const i3 = indexOf({ x: 0 }, (v1, v2) => v1.x === v2.x);
const i4 = indexOf({ x: 4 }, (v1, v2) => v1.x === v2.x);
/*
i0 === 0
i1 === 2
i2 === 4
i3 === 1
i4 === -1
*/
The default compare function checks deep equality, so you will rarely need to pass that parameter.
How to Check All Nodes
There are a few ways to iterate over or display a linked list.
forEach(callback: ListIteratorFunction<T>): void
Runs a callback function on all nodes in a linked list from head to tail:
list.addTail('a');
list.addTail('b');
list.addTail('c');
// "a" <-> "b" <-> "c"
list.forEach((node, index) => console.log(node.value + index));
// 'a0'
// 'b1'
// 'c2'
*[Symbol.iterator]()
A linked list is iterable. In other words, you may use methods like for...of on it.
list.addTail('a');
list.addTail('b');
list.addTail('c');
// "a" <-> "b" <-> "c"
for(const node of list) {
console.log(node.value);
}
// 'a'
// 'b'
// 'c'
toArray(): T[]
Converts a linked list to an array:
list.addTail('a');
list.addTail('b');
list.addTail('c');
// "a" <-> "b" <-> "c"
const arr = list.toArray();
/*
arr === ['a', 'b', 'c']
*/
toString(): string
Converts a linked list to a string representation of nodes and their relations:
list.addTail('a');
list.addTail(2);
list.addTail('c');
list.addTail({ k: 4, v: 'd' });
// "a" <-> 2 <-> "c" <-> {"k":4,"v":"d"}
const str = list.toString();
/*
str === '"a" <-> 2 <-> "c" <-> {"k":4,"v":"d"}'
*/